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"You are a Wilderness Guardian. That northern wasteland; that land of blood, desolation and death is your dominion. Tonight we are going home." ~His Lordship |
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Posted: May 12, 2008 05:55 am  | |
      IRC Nickname: Kiwi011 Group: Emeritus Posts: 3052 Member No.: 40 Joined: December 30, 2007 Total Events Attended: 21    | do u no if this is the formula basically to approximate a derivative using the slope of a secant line? f'(x)=(f(x+h)+f(x))/h just need that answered real quck. A Secant is 1/tangent btw. --------------------  |
Posted: May 12, 2008 12:43 pm | |
 IRC Nickname: Wayne|Eregion2 Group: Emeritus Posts: 3087 Member No.: 156 Joined: January 25, 2008 Total Events Attended: 8 | I THINK it's f'(x)=(f(x+h)-f(x))/h, but I'm not 100% sure. --------------------  |
Posted: June 5, 2008 09:42 pm | |
| IRC Nickname: Crucio01 Group: Clan Friend Posts: 162 Member No.: 750 Joined: June 2, 2008 Total Events Attended: 0 | This is like algebra right? well im learning the first parts of it and that is too complex =[ --------------------   |
Posted: June 6, 2008 05:10 am | |
 IRC Nickname: Matt|Georgio9 Group: Emeritus Posts: 706 Member No.: 94 Joined: January 3, 2008 Total Events Attended: 0 | If you're approximating a point by means of a tangent line.... f(x) = f(a) + f'(a)(x-a) where x is the point you are trying to find an approximate value for. where a is a known point and f(a) a known value. but I think you're doing first principles, possibly the most useless thing you learn. f'(a) = lim ( f(a+h) - f(a) ) / h h->0 --------------------   |
Math Question