The Wilderness Guardians (IPB1 Forums Archive)
Welcome Guest
. : News : . . : Message of the Week : .
You are currently viewing an archive of the Wilderness Guardians clan's IPB1 forums.

These forums were used by WG from 2008 to 2011, and now exist for historical and achival purposes only.

For the clan's current forums, CLICK HERE. 		"You are a Wilderness Guardian. That northern wasteland; that land of blood, desolation and death is your dominion. Tonight we are going home."
~His Lordship
War Alert: OFF Raid Alert: OFF
PM a WG Official
 Ideal gas question
 
Narita
Posted: October 21, 2008 09:01 pmTop
   
User Avatar

IRC Nickname: [Narita]
Group: Guest
Posts: 695
Member No.: 1378
Joined: October 15, 2008
Total Events Attended: 34
 just wondering using pV=nRT with these values
p=1.01x10^5
V=250cm^3
R=8.3
T=293K

i get 10.38 but answer says its 0.0104mol

any help? seems im 2 order of magnitudes out.

the book could be wrong but wanted a second opionon
 
--------------------
Yingyang06
Posted: October 21, 2008 09:20 pmTop
   
User Avatar

IRC Nickname: Yingy
Group: Clan Friend
Posts: 2205
Member No.: 27
Joined: December 30, 2007
Total Events Attended: 21
 1,010,000 x 15,625,000 = 16,635,000

= 8.3 x 293000 x n

= 2,431,900 / 16,635,000

= 6.8403

n = 6.8mol dm-3
 
--------------------
Friend's Forver
The Long Road Ahead - 91/99 Prayer
user posted image
user posted image
Aardvark39
Posted: October 21, 2008 09:25 pmTop
   
User Avatar

IRC Nickname: Aardvark
Group: Banned
Posts: 759
Member No.: 322
Joined: March 13, 2008
Total Events Attended: 175
 [16:21] <Aardvark|work> dont you have to convert to kelvin [Narita] or did you already?
[16:22] <Aardvark|work> i dont really remember that much
[16:23] <Aardvark|work> like convert the temperature to kelvin
[16:23] <Aardvark|work> or something like that
 
--------------------
user posted imageuser posted imageuser posted image
Narita
Posted: October 21, 2008 09:25 pmTop
   
User Avatar

IRC Nickname: [Narita]
Group: Guest
Posts: 695
Member No.: 1378
Joined: October 15, 2008
Total Events Attended: 34
 your pressures wrong its 101,000 not 1,010,000 and where did you get 293,000k?

it was 20 deg C changed to 293K
 
--------------------
Aardvark39
Posted: October 21, 2008 09:29 pmTop
   
User Avatar

IRC Nickname: Aardvark
Group: Banned
Posts: 759
Member No.: 322
Joined: March 13, 2008
Total Events Attended: 175
 Might try google , im sure there are alot of websites etc with people having the same problem, just google the main formula
wink.gif
 
--------------------
user posted imageuser posted imageuser posted image
NightRawrs
Posted: October 21, 2008 09:30 pmTop
   
User Avatar

IRC Nickname: Jesseh
Group: Guest
Posts: 2670
Member No.: 297
Joined: March 8, 2008
Total Events Attended: 222
 Good luck with that Olly tongue.gif

Looks err fun biggrin.gif
 
--------------------
user posted image
user posted image
17/6/08--> 12/9/08--> 29/11/08--> 5/1/09--> 2/3/09(Left)--> 19/7/09(Rejoin)--> 2/8/09
QUOTE
�21:48:06� * @Abs|Busy sexes Jesseh
Narita
Posted: October 21, 2008 09:34 pmTop
   
User Avatar

IRC Nickname: [Narita]
Group: Guest
Posts: 695
Member No.: 1378
Joined: October 15, 2008
Total Events Attended: 34
 not urgent ill just phone my bro tomo
 
--------------------
Aardvark39
Posted: October 21, 2008 09:39 pmTop
   
User Avatar

IRC Nickname: Aardvark
Group: Banned
Posts: 759
Member No.: 322
Joined: March 13, 2008
Total Events Attended: 175
 kk good luck biggrin.gif
http://en.wikipedia.org/wiki/Ideal_gas_law
 
--------------------
user posted imageuser posted imageuser posted image
Narita
Posted: October 21, 2008 09:45 pmTop
   
User Avatar

IRC Nickname: [Narita]
Group: Guest
Posts: 695
Member No.: 1378
Joined: October 15, 2008
Total Events Attended: 34
 never trust wikipedia
 
--------------------
Kiwi011
Posted: October 21, 2008 10:06 pmTop
   
User Avatar

IRC Nickname: Kiwi011
Group: Emeritus
Posts: 3052
Member No.: 40
Joined: December 30, 2007
Total Events Attended: 21
 Sorry, I forgot everything I learned last year in Physics the moment I finished the Final.
 
--------------------
user posted image
Yingyang06
Posted: October 21, 2008 10:23 pmTop
   
User Avatar

IRC Nickname: Yingy
Group: Clan Friend
Posts: 2205
Member No.: 27
Joined: December 30, 2007
Total Events Attended: 21
QUOTE (Narita @ October 21, 2008 09:25 pm)
your pressures wrong its 101,000 not 1,010,000 and where did you get 293,000k?

it was 20 deg C changed to 293K

Try to be more specific, K on these forums means Thousand, not Kelvin.

http://hyperphysics.phy-astr.gsu.edu/hbase...tic/idegas.html
 
--------------------
Friend's Forver
The Long Road Ahead - 91/99 Prayer
user posted image
user posted image
Narita
Posted: October 21, 2008 11:13 pmTop
   
User Avatar

IRC Nickname: [Narita]
Group: Guest
Posts: 695
Member No.: 1378
Joined: October 15, 2008
Total Events Attended: 34
 no it means kelvin when related to a physics thermodynamics question where the value is commonly stated in kelvin.
 
--------------------
Mangomaniac2
Posted: October 21, 2008 11:30 pmTop
   


IRC Nickname: Mangomaniac2
Group: Emeritus
Posts: 536
Member No.: 70
Joined: December 31, 2007
Total Events Attended: 63
QUOTE (Narita @ October 21, 2008 09:01 pm)
just wondering using pV=nRT with these values
p=1.01x10^5
V=250cm^3
R=8.3
T=293K

i get 10.38 but answer says its 0.0104mol

I think its your R thats off.

In the equation,
P = 101,000 Pascals = 1atm
V = 250cm^3 = 250mL = 0.250L
R = 0.0821 atm-L/mol-K
T = 293K

Thus:
PV = nRT
(1atm)(0.250L) = (n)(0.0821atm-L/mol-K)(293K)
n = 0.0104moles

EDIT: P.S. This would have been an appropriate question for the study room tongue.gif
 
--------------------
user posted image
Narita
Posted: October 22, 2008 03:13 pmTop
   
User Avatar

IRC Nickname: [Narita]
Group: Guest
Posts: 695
Member No.: 1378
Joined: October 15, 2008
Total Events Attended: 34
 R is a constant so cant be changed its the molar gas constant 8.3

the asnwe was that .25m^3 it alot.
 
--------------------
Georgio9
Posted: October 22, 2008 08:30 pmTop
   
User Avatar

IRC Nickname: Matt|Georgio9
Group: Emeritus
Posts: 706
Member No.: 94
Joined: January 3, 2008
Total Events Attended: 0
QUOTE (Mangomaniac2 @ October 21, 2008 11:30 pm)
QUOTE (Narita @ October 21, 2008 09:01 pm)
just wondering using pV=nRT with these values
p=1.01x10^5
V=250cm^3
R=8.3
T=293K

i get 10.38 but answer says its 0.0104mol

I think its your R thats off.

In the equation,
P = 101,000 Pascals = 1atm
V = 250cm^3 = 250mL = 0.250L
R = 0.0821 atm-L/mol-K
T = 293K

Thus:
PV = nRT
(1atm)(0.250L) = (n)(0.0821atm-L/mol-K)(293K)
n = 0.0104moles

EDIT: P.S. This would have been an appropriate question for the study room tongue.gif

Fruit beat me to it. ANYWAYS ya so you frigged up you're units which is why you're answer was off.

Pressure is in kPa or atm or bar or mmHg if you really want to.
Volume is in litres (L)
n is mols....self explanatory
T is in kelvin (K)
R depends on you're other variables. If you're using kPa, R = 8.3134 (kPa)(L)/mol(K)


 
--------------------
user posted imageuser posted image