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I need some math help.

By Kiwi011 on 13/03/2008
Can someone tell me what the graph of x^x would look like or be?(Thats X to the power of X)


But yea, help? I am so lost its not even funny. And don't try a graphing calculator, it doesn't work, it does a graph but not the correct one.

By Dalejamesw on 13/03/2008
1+1=2 ..

Hey Kiwi <3

By Kiwi011 on 13/03/2008
QUOTE (Dalejamesw @ March 13, 2008 10:28 pm)
1+1=2 ..

Hey Kiwi <3

X^X

not x+x......

I need a graph of x to the power of x where x is any real number.

By Elyxiatic on 13/03/2008
y = x^x

Now take x = 1
y = 1^1 = 1

Take x = 2
y = 2^2 = 4

Take x = 3
y = 3^3 = 3*3*3 = 27

Take x = 4
y = 4^4 = 4*4*4*4 = 256

So the curve of the graph is exponential.
But that's a gay question, so yeah.
It will go up to infinity hash.png
But that's the positive side only

For negative side -
Take x = -1
y = -1

Take x = -2
y = (-2)^(-2)
y = 1/[(-2)^2]
y = 1/4

Take x = -3
y = (-3)^(-3)
y = 1/[(-3)^3]
y = -1/27

Take x = -4
y = (-4)^(-4)
y = 1/[(-4)^4]
y = 1/[16*16]
y = 1/256

So for the negative side, the function keeps oscillating between positive + negative values, which keep approaching 0.

By Kiwi011 on 13/03/2008
QUOTE (Mathsnerd18 @ March 13, 2008 10:44 pm)
y = x^x

Now take x = 1
y = 1^1 = 1

Take x = 2
y = 2^2 = 4

Take x = 3
y = 3^3 = 3*3*3 =  27

Take x = 4
y = 4^4 = 4*4*4*4 = 256

So the curve of the graph is exponential.
But that's a gay question, so yeah.
It will go up to infinity hash.png

well, try using 3/4 and stuff like that or -3/4 and -2/4 and 2/4 and stuff...i get something thats kind of weird. Especially considering some of the fractions are bigger than 1 and some less.

also forgot, with the negatives use it like this -2 would be (-1)(2)^x. Not (-2)^x

By Mr Death 13 on 13/03/2008
user posted image


I made this up in like 5 minutes by just pluging in numbers. I would double check, I don't know if this is right.

By Elyxiatic on 13/03/2008
QUOTE (Kiwi011 @ March 13, 2008 10:49 pm)
also forgot, with the negatives use it like this -2 would be (-1)(2)^x. Not (-2)^x

You can't split up an exponential.
That's like saying 4^4 = 2*2^4.
So my way is correct, it's the whole of x^x.
Not just positive value of x.

Correct way of splitting
for x = (-2)
y = ((-1)^x)*((2)^x)

By bobler2 on 13/03/2008
Ow.

By Kiwi011 on 13/03/2008
QUOTE (Mathsnerd18 @ March 13, 2008 11:01 pm)
QUOTE (Kiwi011 @ March 13, 2008 10:49 pm)
also forgot, with the negatives use it like this -2 would be (-1)(2)^x. Not (-2)^x

You can't split up an exponential.
That's like saying 4^4 = 2*2^4.
So my way is correct, it's the whole of x^x.
Not just positive value of x.

Correct way of splitting
for x = (-2)
y = ((-1)^x)*((2)^x)

no, you see its like this

(-1)(3)= -3
-3^-2 = -1/9
(-3)^-2=1/9

if its not in parentheses it doesn't abide by the rule of signs. Thats why a graphing calculator has -4^2=-16.

By Elyxiatic on 13/03/2008
QUOTE (Kiwi011 @ March 13, 2008 11:14 pm)
QUOTE (Mathsnerd18 @ March 13, 2008 11:01 pm)
QUOTE (Kiwi011 @ March 13, 2008 10:49 pm)
also forgot, with the negatives use it like this -2 would be (-1)(2)^x. Not (-2)^x

You can't split up an exponential.
That's like saying 4^4 = 2*2^4.
So my way is correct, it's the whole of x^x.
Not just positive value of x.

Correct way of splitting
for x = (-2)
y = ((-1)^x)*((2)^x)

no, you see its like this

(-1)(3)= -3
-3^-2 = -1/9
(-3)^-2=1/9

if its not in parentheses it doesn't abide by the rule of signs. Thats why a graphing calculator has -4^2=-16.

Dude
If you have x^x
That means the whole !!!!!!!!! x
Whether x be 3, -2, -4.5 or w/e
You include the negative!!!!
The calculator doesn't, the calculator is stupid.
YOU INCLUDE THE WHOLE X!!! @@@

Dude, i study maths.
Trust me, i'm right.

By Gibble00 on 14/03/2008
It's just a parabola, well the negative and positive sides together.

By Kiwi011 on 14/03/2008
QUOTE (Mathsnerd18 @ March 13, 2008 11:16 pm)
QUOTE (Kiwi011 @ March 13, 2008 11:14 pm)
QUOTE (Mathsnerd18 @ March 13, 2008 11:01 pm)
QUOTE (Kiwi011 @ March 13, 2008 10:49 pm)
also forgot, with the negatives use it like this -2 would be (-1)(2)^x. Not (-2)^x

You can't split up an exponential.
That's like saying 4^4 = 2*2^4.
So my way is correct, it's the whole of x^x.
Not just positive value of x.

Correct way of splitting
for x = (-2)
y = ((-1)^x)*((2)^x)

no, you see its like this

(-1)(3)= -3
-3^-2 = -1/9
(-3)^-2=1/9

if its not in parentheses it doesn't abide by the rule of signs. Thats why a graphing calculator has -4^2=-16.

Dude
If you have x^x
That means the whole !!!!!!!!! x
Whether x be 3, -2, -4.5 or w/e
You include the negative!!!!
The calculator doesn't, the calculator is stupid.
YOU INCLUDE THE WHOLE X!!! @@@

Dude, i study maths.
Trust me, i'm right.

but your not!

Even my text book says your wrong. So does my calculator and so does my teacher, who was a professor at the airforce academy.

Look, try this problem.

y=-2^x

make x=2

the point (x,y)=(2,-4)

user posted image

http://www.mathsisfun.com/graph/graph.html used this site tog et the graph, which is the same as my textbooks


p.s-mr death yours looks the closest so far from what Ive tried. Thanks for the visual.

By Elyxiatic on 14/03/2008
Dude, that graph isn't x^x
You aren't even doing x^x.
You're doing -(2^x).
Which is different.

I'm seriously leaving this thread.
You're multiplying the whole x^x

What you are doing kiwi is graphing this function

y =
{-|x|^|x| for x<0 }
{|x|^|x| for x>0 }

Which is totally different.

By Elyxiatic on 14/03/2008
Btw, my sister has a mathematics degree.
She agrees with me.

I'm leaving this thread tbh.
You're so thick headed.

Oh and umm, that professor must be on crack.
Tell him he's wrong.
Because he is.
Btw, he was a "professor" at an airforce academy.
At an airforce, don't you teach how to fly planes?

Idiot much?
He wouldn't know a thing about maths.

Btw, calculators can't handle those things.
Unless you have a graphics calculator, which actually works
and you put in this --> y = (x)^(x)
Even then, it mightn't work.

Otherwise, you're just retarded.

By Gibble00 on 14/03/2008
Math, it's just a parabola isn't it?

Seems so if you consider both negative and positive values.

Put it into a calculator as Y=(X)^(X) or Y=(-X)^(-X)

I don't understand what you guys are going on about, it's not that difficult is it? I did it in like five secs twenty mins ago when I made my first post.

I don't understand why you're using all these numbers kiwi.

If you're graphing X^X then you just type in Y=(X)^(X)

And aren't decimals and fractions in this situation like .5^.5 imaginary? That I'm not sure about, but I don't know why you would see it as so complicated to graph.

By Kiwi011 on 14/03/2008
QUOTE (Mathsnerd18 @ March 14, 2008 01:33 am)

Btw, he was a "professor" at an airforce academy.
At an airforce, don't you teach how to fly planes?

Idiot much?
He wouldn't know a thing about maths.



THE Airforce Academy

Its the collage for those going into the Airforce and become officers such as West Point(Army officer) and the Naval Academy(Navy officers).
Its known mainly for its great engineering department and Aero department.
He has a Masters or Doctorates degree, cant remember which.


Yea and what I was doing was the negative x value as an example on how you were wrong. And yes X^X can not be graphed on a calculator, cuz then its wrong, i said that.

Gibble- Its not a parabola, use your calculator and go to table, for my class I have to explain what it does, but i don't know what the main part of the graph looks like, unless Mr. Death was correct which i believe most of it is..And no .5^.5 isn't imaginary. Its a real number.

By Gibble00 on 14/03/2008
QUOTE (Kiwi011 @ March 14, 2008 03:22 am)
Yea and what I was doing was the negative x value as an example on how you were wrong. And yes X^X can not be graphed on a calculator, cuz then its wrong, i said that.

Gibble- Its not a parabola, use your calculator and go to table, for my class I have to explain what it does, but i don't know what the main part of the graph looks like, unless Mr. Death was correct which i believe most of it is..And no .5^.5 isn't imaginary. Its a real number.


Yeah, the decimal/fraction thing, I'm thinking of something else, scratch that completely. And I know what you're saying about the negative side.

Yeah, the graph just looks like what Mr. Death posted, simple.

Why would I got to a table on my calculator though? A table is just like a (X,Y) plot rather than a function of Y.


I've taken math through single variable calculus, but I'm still confused on your problem.

A graph of Y=(X)^(X) is just an exponentially increasing curve on the positive side.

HOWEVER

On the negative side the curve approaches the limit of 0, from a negative Y value (third quadrant, I dunno, whatever, you know what I mean).

I'm headed to bed now, if you figure it out tomorrow let us know, or I can figure it out, my math teacher would be happy to explain it.

By Elyxiatic on 14/03/2008
It's a simple problem.
Kiwi made it hard.
+ that's about it.

By Mr Death 13 on 14/03/2008
Yea...no need to fight guys. Just take a look at my graph tongue.gif

By Georgio9 on 14/03/2008
Alright all you kiddies. I decided to take out the math program that I use in calculus and it's never been wrong for any of the crap I've had it draw which believe me is quite impressive.

user posted image

Alright so what this graph says is that y values do not exist for negative values of x.

This is because you're exponent laws state that if you have a number to the power of a negative number such as (x)^(-x), this simply states that you need to inverse the base.

(x)^(-x) = 1/(x)^(x)

so for example if x is equal to -2

(-2)^(-2) = 1/(-2)^(2) = 1/4 = 0.25

Now back to my triple integrals. woeh.gif

EDIT::::::::::::::::::::::::::::::::::::::::::::::::::::::

Thought about some more and I'm wrong. Now, I'm goin to complain to the tards at the University of Waterloo who made the Maple program. Or I probably just screwed up in my graphing commands. Entirely possible since I really don't know the program all that well.

EDIT2:::::::::::::::::::::::::::::::::::::::::::::::::::

This function is fucked up. If I do some numbers in my head, the graph would seem to oscillate over the x axis when the values of x are less than zero.

By T Dwag on 14/03/2008
Wow flaming over math is kinda sad but I think its a parabola. If not then idk.


Brandon

By maxrobinsun on 14/03/2008
Considering that it is the negative side of the program i am going to give it a shot at explaining.

With a negative number you have to include the -/+ sign not just add it afterwards else you will be calculating something completely different (The negative of an absolute value raised to a negative number)
Basically with an even number you will end up with a positive value eg
-2^-2 = 1/(-2)^2 = 1/4
With odd number you will end up with a negative value eg
-3 ^ -3 = 1/(-3)^3 = -1/9

HOWEVER THIS IS THE PART THAT EVERYONE IS DEBATING OVER
The negative graph is not possible to draw because following the previously show logic it must cross the X axis at some point between -2 and -3, however given the formula this is not possible. Because X^X =/= 0

So you see while picking specific points leads you to believe that there is a negative value in actually its impossible to plot.

Hope that helps.

By Elyxiatic on 14/03/2008
QUOTE (Georgio9 @ March 14, 2008 04:52 am)
This function is fucked up. If I do some numbers in my head, the graph would seem to oscillate over the x axis when the values of x are less than zero.

yeahthat.gif
Is exactly what I said.

However it only works for integers.
Rational numbers would be ugly.

By His Lordship on 14/03/2008
Just fail the subject dude.
It's not worth this ****.

By David on 14/03/2008
What type of math is this. My first guess was a parabola. I realized you wouldn't be asking if it was that simple.

It's possible that it IS a parabola, but any value that would have otherwise been negative is reflected across the X-axis.

QUOTE
With odd number you will end up with a negative value eg
-3 ^ -3 = 1/(-3)^3 = -1/9


It wouldn't be 1/-9, it would be 1/-27 because you're cubing the three when you bring it to the bottom of the fraction.

You could use a Graphing Calculator, but you'd have to make sure there are parenthesis around everything you want to indicate as a single value. I'm not sure if that would be faster or slower, depending on how long it takes you to get around your calculator.

By Pyroclastic0 on 14/03/2008
that looks fun
can't be bother to look at it do enough of that in uni
looks like you just ignore the negative part because it's too hard

By Karel Dude on 14/03/2008
Isnt it x=|X|

If not then i fail

By Parth23 Jani on 14/03/2008

Mathsnerd you are wrong.

-2^-2 is not 0.25 , its -0.25.
You'd be right if it was -2^2.

Mr death was spot on for that bit hash.png

By David on 14/03/2008
QUOTE (Parth23 Jani @ March 14, 2008 02:48 pm)
Mathsnerd you are wrong.

-2^-2 is not 0.25 , its -0.25.
You'd be right if it was -2^2.

Mr death was spot on for that bit hash.png

What re you talking about? Either you made a typo, or just got some things mixed around while you were typing.

-2^-2 = 1/(-2)^2 = 1/4 = 0.25

When you bring the exponent to the denominator, you make it a positive exponent. Since the exponent in this example is 2, it would be a -2 squared, which would ALWAYS be positive.

For -2^2, that is simply 4.
(-2)(-2) = 4

By Spicy63 on 14/03/2008
I hate Algebra and Geometry.
I hate Trig even more.
I hate Math.

By Firelion08 on 14/03/2008
QUOTE (Spicy63 @ March 14, 2008 04:45 pm)
I hate Algebra and Geometry.
I hate Trig even more.
I hate Math.

+1

Though, Geometry's kind of fun. neko2.gif

By Parth23 Jani on 14/03/2008
QUOTE (1colonel1 @ March 14, 2008 04:25 pm)
QUOTE (Parth23 Jani @ March 14, 2008 02:48 pm)
Mathsnerd you are wrong.

-2^-2  is not 0.25 , its -0.25.
You'd be right if it was -2^2.

Mr death was spot on for that bit hash.png

What re you talking about? Either you made a typo, or just got some things mixed around while you were typing.

-2^-2 = 1/(-2)^2 = 1/4 = 0.25

When you bring the exponent to the denominator, you make it a positive exponent. Since the exponent in this example is 2, it would be a -2 squared, which would ALWAYS be positive.

For -2^2, that is simply 4.
(-2)(-2) = 4

I dont think it works like that.
It will be -1(1/2^2) i think.
I put the -1 there just to show that the whole thing is negative.
Also , on a calculator -2^-2 = -0.25

By Georgio9 on 14/03/2008
Alright. THe function DOES NOT EXIT when x is less than 0. It's not continuous and the derivative does not exist on that side of the graph either. Therefore, x must be equal to or greater than 0 for the function to exist.

By Elyxiatic on 14/03/2008
QUOTE (Parth23 Jani @ March 14, 2008 06:09 pm)
QUOTE (1colonel1 @ March 14, 2008 04:25 pm)
QUOTE (Parth23 Jani @ March 14, 2008 02:48 pm)
Mathsnerd you are wrong.

-2^-2  is not 0.25 , its -0.25.
You'd be right if it was -2^2.

Mr death was spot on for that bit hash.png

What re you talking about? Either you made a typo, or just got some things mixed around while you were typing.

-2^-2 = 1/(-2)^2 = 1/4 = 0.25

When you bring the exponent to the denominator, you make it a positive exponent. Since the exponent in this example is 2, it would be a -2 squared, which would ALWAYS be positive.

For -2^2, that is simply 4.
(-2)(-2) = 4

I dont think it works like that.
It will be -1(1/2^2) i think.
I put the -1 there just to show that the whole thing is negative.
Also , on a calculator -2^-2 = -0.25

No.

By Kiwi011 on 14/03/2008
QUOTE (Georgio9 @ March 14, 2008 09:06 pm)
Alright. THe function DOES NOT EXIT when x is less than 0. It's not continuous and the derivative does not exist on that side of the graph either. Therefore, x must be equal to or greater than 0 for the function to exist.

Ok, well heres some stuff

Maths was correct about it oscillating in the negatives from postives to negatives.(pre Calc teacher thought i said something different and i interpreted it wrong)--Sorry maths I was wrong tbh =(

Now, Everyone is pretty wrong.

Georgio- It is a function, my teacher made that clear when he explained that to us.

Maths- It does more than oscillate in the negative side, my teacher said "This function does something more on the negative side than just oscillate."(Something like that)

P.S-- Only 1 person who had taken his class in the last 20 years has gotten the equation correct in those taking his pre-calc class, and the person who did it aced the sat math section and missed like 5 questions on the English.
If any of you go to college or university or something. Could you ask your professor tbh.....My teacher said it was pretty much so weird its almost incomprehensible so yea idk.

He said that I am way off on what i showed him. Its not deaths graph or what maths explained so yea.....Unless people want to keep trying just don't post because im extrememly confused so uhh yea.

By David on 15/03/2008
QUOTE (Parth23 Jani @ March 14, 2008 06:09 pm)
QUOTE (1colonel1 @ March 14, 2008 04:25 pm)
QUOTE (Parth23 Jani @ March 14, 2008 02:48 pm)
Mathsnerd you are wrong.

-2^-2  is not 0.25 , its -0.25.
You'd be right if it was -2^2.

Mr death was spot on for that bit hash.png

What re you talking about? Either you made a typo, or just got some things mixed around while you were typing.

-2^-2 = 1/(-2)^2 = 1/4 = 0.25

When you bring the exponent to the denominator, you make it a positive exponent. Since the exponent in this example is 2, it would be a -2 squared, which would ALWAYS be positive.

For -2^2, that is simply 4.
(-2)(-2) = 4

I dont think it works like that.
It will be -1(1/2^2) i think.
I put the -1 there just to show that the whole thing is negative.
Also , on a calculator -2^-2 = -0.25

What?

If this is what you're given: 2^-2 and you're asked to simplify you'd follow this procedure:
2^-2 --> 1/2^2 --> 1/4 --> .25

I have no idea where you're getting your figures from.

Put this into the calculator:
(-2)^(-2) you'll get a positive .25.

By Gibble00 on 15/03/2008
QUOTE (Kiwi011 @ March 14, 2008 10:04 pm)
QUOTE (Georgio9 @ March 14, 2008 09:06 pm)
Alright. THe function DOES NOT EXIT when x is less than 0. It's not continuous and the derivative does not exist on that side of the graph either. Therefore, x must be equal to or greater than 0 for the function to exist.

Ok, well heres some stuff

Maths was correct about it oscillating in the negatives from postives to negatives.(pre Calc teacher thought i said something different and i interpreted it wrong)--Sorry maths I was wrong tbh =(

Now, Everyone is pretty wrong.

Georgio- It is a function, my teacher made that clear when he explained that to us.

Maths- It does more than oscillate in the negative side, my teacher said "This function does something more on the negative side than just oscillate."(Something like that)

P.S-- Only 1 person who had taken his class in the last 20 years has gotten the equation correct in those taking his pre-calc class, and the person who did it aced the sat math section and missed like 5 questions on the English.
If any of you go to college or university or something. Could you ask your professor tbh.....My teacher said it was pretty much so weird its almost incomprehensible so yea idk.

He said that I am way off on what i showed him. Its not deaths graph or what maths explained so yea.....Unless people want to keep trying just don't post because im extrememly confused so uhh yea.

tongue.gif

Goddamn. F your teacher man, rolleyes.gif, not even gonna explain it for us.

Tell him I want to know sad.gif

By Parth23 Jani on 15/03/2008
QUOTE (1colonel1 @ March 15, 2008 01:29 am)
QUOTE (Parth23 Jani @ March 14, 2008 06:09 pm)
QUOTE (1colonel1 @ March 14, 2008 04:25 pm)
QUOTE (Parth23 Jani @ March 14, 2008 02:48 pm)
Mathsnerd you are wrong.

-2^-2  is not 0.25 , its -0.25.
You'd be right if it was -2^2.

Mr death was spot on for that bit hash.png

What re you talking about? Either you made a typo, or just got some things mixed around while you were typing.

-2^-2 = 1/(-2)^2 = 1/4 = 0.25

When you bring the exponent to the denominator, you make it a positive exponent. Since the exponent in this example is 2, it would be a -2 squared, which would ALWAYS be positive.

For -2^2, that is simply 4.
(-2)(-2) = 4

I dont think it works like that.
It will be -1(1/2^2) i think.
I put the -1 there just to show that the whole thing is negative.
Also , on a calculator -2^-2 = -0.25

What?

If this is what you're given: 2^-2 and you're asked to simplify you'd follow this procedure:
2^-2 --> 1/2^2 --> 1/4 --> .25

I have no idea where you're getting your figures from.

Put this into the calculator:
(-2)^(-2) you'll get a positive .25.

**** , you're right hash.png

ph34r.gif

By Pazenon on 15/03/2008
Epic fail Parth hash.png



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